Friday, April 30, 2010
Exit Slip 11.4
The overall task of this PBAT is to find the radius, height, volume, surface area, of a can. Once you find all these values we will put the equation in on a computer program and play with different volumes of the same can.
Tuesday, April 27, 2010
Exit Slip 11.4 4/27
The important concept about today's lesson was learning how to find the height using radius and volume.
I used a calculator today. A calculator was helpful because it helped me to multiply my big numbers. Using the tool made my life easier because i didn't need to use a pen and paper to multiply my numbers.
I used a calculator today. A calculator was helpful because it helped me to multiply my big numbers. Using the tool made my life easier because i didn't need to use a pen and paper to multiply my numbers.
Friday, April 23, 2010
Exit Slip 4.23.10 Michelle D
Today I helped Raquel by telling her what the surface area calculation was. I was also helped by others in the classroom because they told me what I missed yesterday.
I was able to accomplish everything on my sheet with surface area and volume.
The skills I learned today was how to measure the diameter of a can, and also measure the height. In the real world my skills may come in handy because my son or daughter will be in high school one day. I also have a little sister that is doing this exact thing in math this semester.
My last question on this topic is, How do you determine the dimensions when labeling your work.
I was able to accomplish everything on my sheet with surface area and volume.
The skills I learned today was how to measure the diameter of a can, and also measure the height. In the real world my skills may come in handy because my son or daughter will be in high school one day. I also have a little sister that is doing this exact thing in math this semester.
My last question on this topic is, How do you determine the dimensions when labeling your work.
Wednesday, April 21, 2010
Writing objectively MD 11.4
There are two functions shown in this three column table. The first function is y1=4x^3+5, and the second function is, y2=7x^3+100. The results of these two functions are shown in the first column "x".
The first column contains some values for the independent variable x. These values range from: -25 to 25. The scale is set to 5.
These x values were substituted into the function, and the results are displayed in the second and third columns. Since these are quadratic functions, the y-values first decrease as x-values increase from negative numbers to zero. For the first function,(0,5) is the vertex, and for the second function (0,100) is the vertex. Which is also the minimum pointon the graph. Then, the y-values increase as x increases from 0 to positive values.
The first column contains some values for the independent variable x. These values range from: -25 to 25. The scale is set to 5.
These x values were substituted into the function, and the results are displayed in the second and third columns. Since these are quadratic functions, the y-values first decrease as x-values increase from negative numbers to zero. For the first function,(0,5) is the vertex, and for the second function (0,100) is the vertex. Which is also the minimum pointon the graph. Then, the y-values increase as x increases from 0 to positive values.
Thursday, April 15, 2010
11.4 exit slip Michelle Decosta
The curvature of y2 compared to y1 is neither wider, but it is reflected on the x-axis.
Compared to y1, y2's graph is shifted vertically . We see this in the graph by noting that the equation 3x^2+100 compared to 5x^2-100 makes the equation wider, because the smaller the number is to the second power the wider the line will be.
There is no horizontal shift because the lines have the same pattern horizontally. The minimums line up at x=+-100
Compared to y1, y2's graph is shifted vertically . We see this in the graph by noting that the equation 3x^2+100 compared to 5x^2-100 makes the equation wider, because the smaller the number is to the second power the wider the line will be.
There is no horizontal shift because the lines have the same pattern horizontally. The minimums line up at x=+-100
Tuesday, April 13, 2010
exit slip 11.4 4/13/10
y1=-3x+20^2+2
y2=3x+20^+2
The two graphs that were created are different. They differ because my Y1 line was a complete reflection of my Y2.
I went about comparing my graphs by going to Google spreadsheet and entering both equations.
Once I entered the equations I dragged down both equations in there row and it calculated the numbers for me. After that Both my lines were shown into my graphs, and all I had to do was title my graph. After titling i realized that my y1 line is a complete reflection.
After completing my comparison between lines I created a table that shows my highest degree term, my constant term, and my terms that were used such as, Y1 and Y2.
y2=3x+20^+2
The two graphs that were created are different. They differ because my Y1 line was a complete reflection of my Y2.
I went about comparing my graphs by going to Google spreadsheet and entering both equations.
Once I entered the equations I dragged down both equations in there row and it calculated the numbers for me. After that Both my lines were shown into my graphs, and all I had to do was title my graph. After titling i realized that my y1 line is a complete reflection.
After completing my comparison between lines I created a table that shows my highest degree term, my constant term, and my terms that were used such as, Y1 and Y2.
Friday, April 9, 2010
Exit slip!
1) One major idea I learned today was that spreadsheet can be a very easy way to graph a function. Using spreadsheet will make my life much easier.
2) One major problem I had today was not remembering to go Firefox, and also when using spreadsheet how to do my function to the "y" axis.
2) One major problem I had today was not remembering to go Firefox, and also when using spreadsheet how to do my function to the "y" axis.
Subscribe to:
Posts (Atom)